Check if a given number is even or odd

Given a number,check if it is even or odd using bit operations.

Algorithm: let num be x find x&1 ,if result is 0 then even else odd. The Least significant bit of odd number is always 1 and even is always 0, hence x&1 will be 0 if even else odd.

Implementation

    def check_evenOdd(x)
        if x&1==0
            print "#{x} is even"
        else
            print "#{x} is odd"
        end
    end